Observation 24450: Polyporales sensu lato
When: 2009-08-14
Collection location: Prairie Creek Redwoods State Park, Humboldt Co., California, USA [Click for map]
Who: Debbie Viess (amanitarita)
No specimen available
Notes:
A large and handsome grouping of polypores on dead old growth Doug Fir. Very tricky shot, balancing on another downed monster tree…no specimen (or close-up) possible!
Images
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 5.96 | 1 | ||||||
| Could Be | 1.0 | 0.00 | 0 | ||||||
| Doubtful | -1.0 | 0.00 | 0 | ||||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 5.64 | 1 | (myxomop) | |||||
| Overall Score sum(score * weight) / (total weight + 1) |
-0.40 | -13.24% | |||||||
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 0.00 | 0 | ||||||
| Could Be | 1.0 | 5.64 | 1 | (myxomop) | |||||
| Doubtful | -1.0 | 0.00 | 0 | ||||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 0.00 | 0 | ||||||
| Overall Score sum(score * weight) / (total weight + 1) |
0.85 | 28.32% | |||||||
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 5.64 | 1 | (myxomop) | |||||
| Could Be | 1.0 | 0.00 | 0 | ||||||
| Doubtful | -1.0 | 0.00 | 0 | ||||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 0.00 | 0 | ||||||
| Overall Score sum(score * weight) / (total weight + 1) |
1.70 | 56.63% | |||||||