Observation 268867: Strophariaceae Singer & A.H. Sm.
When: 2017-01-31
Collection location: Marys Peak aka Mary’s Peak, Benton Co., Oregon, USA [Click for map]
259m
Who: Insporeations (Eric Badeau)
Specimen available
Fungarium record:
Notes:
Found these in a mixed second growth Conifer forest fruiting of what I believe to be a Douglas Fir Cone.
Species Lists
Images
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 0.00 | 0 | ||||||
| Could Be | 1.0 | 4.62 | 1 | (Eric Badeau) | |||||
| Doubtful | -1.0 | 5.29 | 1 | (Pulk) | |||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 0.00 | 0 | ||||||
| Overall Score sum(score * weight) / (total weight + 1) |
-0.06 | -2.02% | |||||||
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 5.29 | 1 | (Pulk) | |||||
| Could Be | 1.0 | 0.00 | 0 | ||||||
| Doubtful | -1.0 | 0.00 | 0 | ||||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 0.00 | 0 | ||||||
| Overall Score sum(score * weight) / (total weight + 1) |
1.68 | 56.06% | |||||||
| User’s votes are weighted by their contribution to the site (log10 contribution). In addition, the user who created the observation gets an extra vote. | |||||||||
| Vote | Score | Weight | Users | ||||||
|---|---|---|---|---|---|---|---|---|---|
| I’d Call It That | 3.0 | 0.00 | 0 | ||||||
| Promising | 2.0 | 0.00 | 0 | ||||||
| Could Be | 1.0 | 4.28 | 1 | (maynardjameskeenan) | |||||
| Doubtful | -1.0 | 0.00 | 0 | ||||||
| Not Likely | -2.0 | 0.00 | 0 | ||||||
| As If! | -3.0 | 0.00 | 0 | ||||||
| Overall Score sum(score * weight) / (total weight + 1) |
0.81 | 27.02% | |||||||